算法描述：

Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it .

Example 1:

Input: [  [1,1,1],  [1,0,1],  [1,1,1]]Output: [  [1,0,1],  [0,0,0],  [1,0,1]]

Example 2:

Input: [  [0,1,2,0],  [3,4,5,2],  [1,3,1,5]]Output: [  [0,0,0,0],  [0,4,5,0],  [0,3,1,0]]

Follow up:

• A straight forward solution using O(mn) space is probably a bad idea.
• A simple improvement uses O(m + n) space, but still not the best solution.
• Could you devise a constant space solution?

解题思路：将矩阵的首行和首列用于标记该行或该列中有0元素。而首行和首列则需要单独的标记位标记该行或者列中有0元素存在。

void setZeroes(vector
     
      
       >& matrix) {        int m = matrix.size();        int n = matrix[0].size();        bool row = false;        bool col = false;        for(int i=0; i < m; i++) if(matrix[i][0]==0) row = true;        for(int j=0; j < n; j++) if(matrix[0][j]==0) col = true;        for(int i=1; i < m; i++){            for(int j=1; j < n; j++){                if(matrix[i][j]==0){                    matrix[i][0]=0;                    matrix[0][j]=0;                    }            }        }        for(int i = 1; i < m; i++){            for(int j =1; j < n; j++){                if(matrix[i][0]==0 || matrix[0][j]==0){                    matrix[i][j]=0;                }            }        }        if(row)            for(int i=0; i < m; i++) matrix[i][0]=0;        if(col)            for(int i=0; i < n; i++) matrix[0][i]=0;    }